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The integral ∫ sec^2/3 x cosec^2/3 x dx x∈[π/6, π/3] is equal to :

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The integral ∫ sec2/3 x cosec2/3 x dx  x∈[π/6, π/3]  is equal to : 

(1)  35/3 - 31/3

(2)  35/6 - 32/3

(3)  34/3 - 31/3

(4)  37/6 - 35/6

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Correct option  (4)  37/6 - 35/6

Explanation:

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