Question

Two soap bubbles have radius 0.5 cm and 1.0 cm. The difference in pressure inside the them is 14 N/m². Calculate the surface tension of the soap solution.

Answer 1

R₁ = 0.5cm = 0.5 x 10^-2 m;

R₂ = 1.0 cm = 1.0 x 10^-2 m;

∆P = 14 N/m²; T = ?

∆P = ∆P₁ - ∆P₂ = \(\frac{4T}{R_1} - \frac{4T}{R_2}\)