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1 Answer

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by (41.3k points)

Given,

\(m\sin \theta = n \sin (\theta + 2\alpha)\)

\(\frac mn = \frac {\sin(\theta + 2 \alpha )}{\sin \theta}\)

Apply componendo and dividendo

\(\frac{m + n}{m-n} = \frac {\sin (\theta + 2\alpha) + \sin \theta}{\sin (\theta + 2\alpha) - \sin \theta}\)

\(\frac{m + n}{m-n} = \frac {\sin (\theta + \alpha) \cos \alpha}{\cos(\theta + \alpha) \sin \alpha}\)

\(\frac{m + n}{m-n} = \tan(\theta + \alpha) \cot \alpha\) 

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