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3.2 g oxygen is diffused in 10 minutes. In similar conditions, 2.8 g nitrogen will diffuse in

(a) 9.3 minutes

(b) 8.2 minutes

(c) 7.6 minutes

(d) 11.8 minutes

1 Answer

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Best answer

Correct option is (a) 9.3 minutes

As we know,

Rate of diffusion \(\propto \sqrt{\frac 1M}\)

\(\therefore \frac{\frac 1{t_{O_2}}}{\frac1{t_{N_2}}} = \sqrt{\frac{M_{N_2}}{M_{O_2}}} = \sqrt {\frac{2.8}{3.2}} = 0.93\)

or \(\frac{t_{N_2}}{t_{O_2}} = 0.93\)

\(\therefore t_{N_2} = 0.93 \times 10 = 9.3 \ min\)

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