Correct option is (c) is changed by 26%
Remember that partial pressure of a gas mole fraction
Mole fraction of O2 at start = \(\frac 3{10} \times 100 = 30\)
Mole fraction of O2 at final stage = \(\left(\frac 3{10} - \frac 29\right) \times 100 = \frac{70}9 \approx 8\)
\(\therefore \) % change = \(\frac 8 {30} \times 100 \approx 26 \) %