Question

Calculate mean free path of nitrogen molecule at 27°C temperature while pressure is 1.5 atmosphere. (Diameter of nitrogen molecule = 1.5 Å, k= 1.38 x 10^-23 JK^-1)

Answer 1

T = 27 + 273 = 300 K;

P = 1.5 atm = 1.5 x 1.01 x 10⁵ N.m^-2

d = 1.5 Å = 1.5 x 10^-10 m; k = 1.38 x 10^-23; λ = ?