Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
167 views
in Physics by (71.4k points)
closed by

Show that simple harmonic function may be regarded as the projection of uniform circular motion along a diameter of the circle. Hence derive an expression for the displacement of a particle in S.H.M.

1 Answer

+1 vote
by (69.3k points)
selected by
 
Best answer

Using Newtons second law of motion and the expression for acceleration of a particle undergoing S.H.M., the force acting on a particle of mass M in S.H.M. is:

f(t) = ma

= -mω2 (xt)

i.e., f(t) = -kx (t)

where k = mω2

or \(\omega = \sqrt{\frac{k}{m}}\) 

Like acceleration, force is always directed towards mean position.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...