Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
26 views
in Physics by (24.9k points)
closed ago by

When two displacements represented by y1 = a sin ωt and y2 = b cos ωt are superimposed, then the motion is

(a) Not a simple harmonic

(b) Simple harmonic with amplitude a/b

(c) Simple harmonic with amplitude \(\sqrt{(a^2 + b^2)}\)

(d) Simple harmonic with amplitude \((\frac{a + b}{2})\)

1 Answer

+1 vote
by (25.3k points)
selected ago by
 
Best answer

Given y1 = a sin ωt

y2 = b sin ωt

= b sin (ωt + \(\frac{\pi}{2}\))

The resultant displacement is given by

y = y1 + y2

\( = \sqrt{(a^2 + b^2)}sin(\omega t +\phi )\)

Hence the motion of superimposed wave is simple

harmonic with amplitude \(\sqrt{(a^2 + b^2)}\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...