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In XeF4, hybridisation of Xe is

(a) sp3d2

(b) sp3

(c) sp3d

(d) sp2

1 Answer

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Best answer

Correct option is (a) sp3d2

XeF4 molecule has 4 bond pairs and 2 lone pairs in the molecule. So all the electron pairs surrounding the atom are 6 i.e lone pairs and bond pairs. Hence hybridization is sp3d2.

The geometry of the molecule is octahydral.

But the shape of the molecule is square planar shape, due to lone pair- bond pair arrangement.

XeF4 molecule has 4 bond pairs and 2 lone pairs in the molecule

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