Question

The effective atomic number of 'Cr' in  [Cr (NH₃)₆]Cl₃

(a) 35

(b) 36

(c) 27

(d) 33

Answer 1

To find the effective atomic number in  [Cr(NH₃)₆]Cl₃ 

Atomic Number of Cr= 24

Oxidation state of Cr= +3

Number of Ligands= 6

We have a formula:

Effective Atomic Number(EAN) = Atomic number + 2(Number of ligands) - Oxidation state

EAN = 24 + 2(6) - 3

EAN = 24 + 12 - 3

EAN = 33

=> Option (D) = 33 is correct.

Comments

Good explanation

Answer 2

Correct option is (d) 33

Cr⁺³(NH₃)₆]Cl₃

EAN = 24 + 2 x 6 - 3

= 33