Question

The equivalent mass of \( MnSO _{4} \) is half of its molecular mass when it is converted to 

(1) \( Mn _{2} O _{3} \)

(2) MnO

(3) \( MnO _{2} \)

(4) \( MnO _{4} \)

Answer 1

The correct option is (3) MnO₂.

Here, change in the oxidation of Mn = 2.

So, n−factor = 2.

Equivalent weight = \(\frac{M}{2}\)

Therefore, the equivalent weight of MnSO₄ is half of its molecular weight when it is converted to MnO₂.