Correct option is (B) 90
HCF = \((3^3 \times 5^2 \times 2, 3^2 \times 5^3 \times 2^2, 3^4 \times 5 \times 2^3)\)
H.C.F. = Product of smallest power of each common prime factor in the numbers
\(= 2 \times 3^2 \times 5\)
\(= 2 \times 3^2 \times 5\)
\(= 90\)