To determine which of the given compounds will not show geometrical (cis-trans) isomerism, let's analyze each structure:
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(a) The given structure is a cyclic compound with two hydroxyl (-OH) groups attached to a small ring. Cyclic compounds can exhibit geometrical isomerism if two different groups are attached to the ring in a way that prevents free rotation. In this case, it is possible.
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(b) and (c) Both structures contain a cyclohexane or substituted cyclohexane ring with different groups attached. If there are two identical groups (such as Br in (b)), they can exist in cis and trans forms.
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(d) The structure is 1,4-dibromobenzene, which is a symmetrically substituted benzene ring. In benzene rings, free rotation is not possible, but geometrical isomerism does not exist for para (1,4) substitution because both bromine atoms are fixed in the same relative position.
Conclusion:
(d) 1,4-Dibromobenzene does not show geometrical isomerism.
Thus, the correct answer is option (d).
