Question

Two wires are similar and they are in the same tone. When there is increase of 1% in the tension of one wire, then on sounding both at the same time, 3 beats are heard in 2 s. Find the initial frequency of both the wire.

Answer 1

Beat frequency = \(\frac{3}{2}\) per second

\(or\ \frac{v_2 - v_1}{v_1} = \frac{1}{200}\)

Given : \(v_2 -v_1 = \frac{3}{2}\)

\(\therefore\ \frac{3/2}{v_1} = \frac{1}{200}\Rightarrow v_1 = 2000\times\frac{3}{2} = 3000Hz\)

\(\therefore\ v_1 = 300\ Hz\) 

Based on Beats