Question

Calculate the number of Cl ̄ ions in 0.585 g of NaCl.

Answer 1

Thus, no. of NaCl molecules in 0.585 g will be 

\( = \frac{6.022\times10^{23}\times 0.585}{58.5}\) NaCl molecules

= 6.022 × 10²¹ NaCl molecules 

1 molecule of NaCl contains = Cl^- 

6.022 × 10²¹ molecule of NaCl will contain 

 = 6.022 × 10²¹ CI ions.