Question

Calculate the number of atoms present in 3.2 g of sulphur.

Answer 1

Atomic weight of S = 32 

No. of atoms in 32 g S = 6.022 × 10²³ 

No. of atoms in 3.2 g S   = \(\frac{6.022 \times 10^{23}\times32}{32}\)

= 6.022 × 10²²