Question

If 1 g of any gas at N.T.P. occupies 1400 mL volume, what is molecular weight of gas? How much molecules are present in gas at N.T.P.? 

Answer 1

Weight of 1400 mL gas = 1 g

At N.T.P., weight of 22400 mL gas  = \(\frac{22400}{1400}\)

Molecular weight of gas = 16 g 

Number of molecules, at N.T.P. in 22400 mL gas 

= 6.022 × 10²³ molecules 

Hence, number of molecules in 1 mL gas 

\( = \frac{6.022\times 10^{23}}{22400}\)

= 2.688 × 10¹⁹ molecules