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ago in Chemistry by (25.4k points)
closed ago by

Boron occurs in nature in its two isotopes whose atomic masses are 10 and respectively. What will be the % abundance of that sample which has average atomic mass as 10.8? 

1 Answer

+1 vote
ago by (24.9k points)
selected ago by
 
Best answer

Suppose, percentage of B10  = x 

B11 = 100 - x

Average atomic mass of boron 

Average atomic mass of boron

10.8 × 100 = 1100 - x 

1080 = 1100x 

So, percentage of B10 and percentage of B11 = 100 - 20 = 80% 

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