% of O = 100 - (% of Na + % of S + % of H)
= 100 - (14.28 + 9.92 + 6.20) = 100 - 30.40 = 69.60
So, empirical formula of compound = Na2H2OO14
Empirical formula mass = 23 × 2 + 32 + 20 + 14 × 16
46 + 32 + 20 + 224
= 322 g
Molar mass of compound = 322 g
\(n = \frac{\text{Molar} \ \text{mass}}{\text{Empirical}\ \text{formula}\ \text{mass}}\)
\( = \frac{322}{322} = 1\)
Molecular formula of compound is Na2SH2OO14. The formula of crystallized compound will be Na2SO410H2O.