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Density of aqueous solution of 2 M oxalic acid is 1.02 g/mL, if molecular weight of oxalic acid is 126g/mol then calculate the molality of solution. 

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Molarity 'M' = 2 M 

Density 'd' = 1.02 g/mL 

Molecular weight of solute 'MB' = 126 g/mol 

Molality (m) = ? 

2 M' means that 2 mol of solute is dissolved in 1 L solution. 

Volume of solution = 1000 mL 

Density of solution = 1.02 g/mL 

Weight of solution = ? 

So Weight of solution = Density × Volume 

= 1.02 × 1000 = 1020 g

Moles of solute = \(\frac{\text{Weigh} \ \text{of}\ \text{solute}\ (W_B) }{\text{Molecular} \ \text{weight}\ \text{of}\ \text{solute}\ (M_B)}\)

'WB' = Moles of solute × Molecular weight 

= 2 × 126 = 252 g 

Weight of solvent 'WA'  = Weight of solution - Weight of solute

Weight of solvent 'WA'

= 2.604 mol/kg.

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