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Find the particular solution of the differential equation

ex\(\sqrt{1-y^2 dx} + \frac{y}{x}\) dy = 0,

given that y = 1, when x = 0.

1 Answer

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Best answer

Given, differential equation is

differential equation

Also, given that y = 1, when x = 0

On putting y = 1 and x = 0 in Eq, (i), we get

\(\sqrt{1-1}\) = 0 - e0 + C

⇒ c = 1 [∵ e0 = 1]

On substituting the value of C in Eq. (i), we get

\(\sqrt{1-y^2}\) = xeX - ex + 1

which is the required particular solution of given differential equation.

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