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A particle continuously moves in a circular path at constant speed in a counterclockwise direction. Consider a time interval during which the particle moves along this circular path from point P to point Q. Point Q is exactly half-way around the circle from Point P.

What is the direction of the average acceleration during this time interval? 

(A) → 

(B) ← 

(C) ↑ 

(D) ↓ 

(E) The average acceleration is zero.

1 Answer

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Best answer

Correct option (D) ↓

The velocity is initially pointing up, the final velocity points down. The acceleration is in the same direction as ∆v = vf + (–vi).

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