Magnetic Flux

Question

An electron is moving in a circular path of radius 0.012 m in a uniform perpendicular magnetic field the speed of electron is 10 to the power of 6 metre per second how much flux is enclosed by the circuit

Answer 1

Given values: radius r = 0.012 m and speed of electron v = 10⁶ m/s.

Area of the circular path: A = πr² = π(0.012)².

Area: A = π x 0.000144 = 0.00045216 m².

Since the magnetic flux Φ is given by Φ = B x A and the magnetic field B is not provided, we cannot compute the exact flux without this value. 

However, the flux formula remains Φ = B x 0.00045216 Wb.

The magnetic flux enclosed by the circuit is Φ = B x 0.00045216 Wb, where B is the magnetic field strength.