Question

Reaction of x g of Sn with HCl quantitatively produced a salt. Entire amount of the salt reacted with y g of nitrobenzene in the presence of required amount of HCl to produce 1.29 g of an organic salt (quantitatively). (Use Molar masses (in g mol^–1) of H, C, N, O, Cl and Sn  as

The value of x is .

Answer 1

Sn + 2HCl → SnCl₂ + H₂

Moles of Sn = \(\frac {x}{119}\)

\( \text {Moles of nitrobenzene }=\frac{x}{119} \times \frac{1}{3}\)

\(\text {Moles of anilium chloride }=\frac{x}{119} \times \frac{1}{3} \)

\(\text {Moles of nitrobenzene }=\frac{x}{357}\)

\( \frac{y}{123}=\frac{x}{357} \) .....(1)

\( \text {Moles of anilium chloride }=\frac{x}{357} \) .....(2)

\( \frac{1.29}{129}=\frac{x}{357}\)

\( x=3.57\)