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The first meters of a 100-meter dash are covered in 2 seconds by a sprinter who starts from rest and accelerates with a constant acceleration. The remaining 90 meters are run with the same velocity the sprinter had after 2 seconds. 

a. Determine the sprinter's constant acceleration during the first 2 seconds. 

b. Determine the sprinters velocity after 2 seconds have elapsed. 

c. Determine the total time needed to run the full 100 meters.

d. On the axes provided below, draw the displacement vs time curve for the sprinter.

1 Answer

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a. For the first 2 seconds, while acceleration is constant, d = ½at2 Substituting the given values d = 10 meters, t = 2 seconds gives a = 5 m/s2

b. The velocity after accelerating from rest for 2 seconds is given by v = at, so v = 10 m/s 

c. The displacement, time, and constant velocity for the last 90 meters are related by d = vt. To cover this distance takes t = d/v = 9s. The total time is therefore 9 + 2 = 11 seconds

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