Question

For a reaction, equilibrium constant is 10 at 300 K. Calculate the ∆G°. (R = 8.314 JK^-1mol^-1)

Answer 1

∆G° = - RT In K = -2.303 RT log Kp

R = 8.314 JK ^-1 mol^-1 

T = 300 K 

Kp = 10 

∆G° = - 2.303 × (8.314 JK^-1 mol^-1) × (300 K) log 10 

= - 5744.14 J mol^-1 

= - 5.744 kJ mol^-1