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N2(g) + 3H2(g) → 2NH3; ∆r H = - 92.4 kJ mol-1. Calculate the enthalpy of formation of gas?

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Standard enthalpy of formation of NH3 gas: 

\(\Delta _fH_{NH_3}^\ominus = \frac{-92.4}{2}\)

= - 46.2 kJ mol-1 

So standard enthalpy of formation of NH3 gas is 46.2 kJ mol-1.

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