The skeletal equation for the reaction is:
Cl2 (aq) + SO2 (aq) + H2O (l) → Cl-(aq) + SO2-(aq)
Reduction half cell: Cl2 (aq) → Cl- (aq)
Balance Cl atoms: Cl2 (aq) → 2Cl- (aq)
Balance O.N. by adding electrons :
Cl2 (aq) + 2e- → 2Cl-(aq)
Oxidation half cell: SO+42 (aq) → SO2-4 (aq) + 2e- + 4H+
Balance O.N. by adding electrons :
SO2 (aq) → SO2-(aq) + 2e-
Balance charge by adding H+ ions :
SO2 (aq) → SO2-(aq) + 2e- + 4H+(aq)
Balance O atom by adding H2O:
SO2 (aq) + 2H2O → SO2-4 (aq) + 2e- + 4H+(aq)
Adding both the equations we get:
Cl2 (aq) + SO2(aq) + 2H2O(l) → 2Cl-(aq) + SO2-(aq) + 4H+
This represents balanced equation.