Question

In figure, if AB || CD and CD || EF. find ∠ACE.

Answer 1

Given: AB || CD and CD || EF

Since, CD||EF

⇒ ∠FEC + ∠ECD = 180°

(Sum of co-interior angles is supplementary)

⇒ ∠ECD = 180° − 130° = 50°

Also, BA || CD

∠BAC = ∠ACD = 70° (Alternate interior angles)

⇒ ∠ACD = 70°

⇒ ∠ACE + ∠ECD = 70°

⇒ ∠ACE = 70° − ∠ECD

⇒ ∠ACE = 70° − 50° = 20°

Hence, ∠ACE = 20°