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Explain why (CH3)C+ is more stable than so CH3 CH+2 and CH+3 is the least stable cation?

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(CH3)3C+ has nine a-hydrogens and hence has nine hyperconjugation structures while CH3CH2+ has only three a-hydrogens and has hence has only three hyperconjugation structures. As a result, (CH3)3C+ is more stable than CH3CH2+.  In contrast in CH, the vacant p-orbital is perpendicular filt to the plane in which C-H bond lie and hence cannot overlap with it. Thus, CH3+ is not stabilized by hyperconjugation and is the least stable of the three cations.

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