(CH3)3C+ has nine a-hydrogens and hence has nine hyperconjugation structures while CH3CH2+ has only three a-hydrogens and has hence has only three hyperconjugation structures. As a result, (CH3)3C+ is more stable than CH3CH2+. In contrast in CH, the vacant p-orbital is perpendicular filt to the plane in which C-H bond lie and hence cannot overlap with it. Thus, CH3+ is not stabilized by hyperconjugation and is the least stable of the three cations.