Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
166 views
in Straight Lines by (20 points)
recategorized by

Find the ratio in which the \( y \)-axis divides the line segment joining the points \( (4,-5) \) and \( (-1,2) \). Also find the point of intersection.

Please log in or register to answer this question.

1 Answer

0 votes
by (18.5k points)

The line segment joining the points (4, -5) and (-1, 2) is divided by the Y-axis.

The point which divides the given line segment. lies on Y-axis. 

Its abscissa is 0.

Let the point (0, y) intersects the line segment joining the point (4, -5) and (-1, 2) in the ratio m : n.

Using Section formula, we have.

\(x=\frac{m x_2+n x_1}{m+n} ; \) \(y=\frac{m y_2+n y_1}{m+h} \)

\(x=\frac{m x_2+n x_1}{m+n} ; \)

\( 0=\frac{m \times(-1)+n(4)}{m+n} ; \)

\( 0=\frac{-m+4 n}{m+n} \)

\(-m+4 n=0 \)

\(-m = -4 n\)

\(\frac {m}{n} = \frac {4}{1}\)

m : n = 4 : 1

\(\text {This implies, } y=\frac{m y_2+n y_1}{m+n}\)

\(=\frac{4 \times 2+1 \times(-5)}{4+1} \)

\( =\frac{8-5}{5}\)

\(=\frac {3}{5}\)

The ratio of division is 4 : 1 and the Coordinates of the point of division are \((0,\frac {3}{5})\).

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...