Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
60 views
in Calculus by (78.6k points)
closed by

First fundamental theorem of integral calculus

1 Answer

+1 vote
by (77.1k points)
selected by
 
Best answer

Theorem 1.

Let f be a continuous function of the closed interval [a, b] and let A(x) be the area function. Then, A'(x) f(x) for all x ∈ [a1 b]

Second fundamental theorem of integral calculus

Theorem 2.

Letf be continuous function defined on the closed interval [a, b] and F be an antiderivative off.

Then, \(\int^x_a\) f(x) dx = [F(x)]_{a}^{b} = F(b) - F(a)

In other words \(\int^x_a\) f(x) dx = (Value of the anti-derivative F off at the upper limit b) - (Value of the same anti-derivative at the lower limit a)

Remarks:

(1) Second fundamental theorem of integral calculus is very useful, because it gives us a method for calculating the definite integral more easily.

(2) In \(\int^x_a\) f(x) dx, the function f needs to be well defined and continuous in [a, bi.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...