Given,
Side of tile = 50 cm
First we change it to Metre
We know,
1 m = 100 cm
100 cm = 1 m
1 cm = 1 / 100 m
50 cm = 50 / 100 m
50 cm = 1 / 2 m
50 cm = 0.5 m
Area of tile = (side)2
= 0.5 x 0.5
Area of tile = 0.25 m2
It is given that tile can carry a pressure of 200 N/m2. If the force applied by this pressure is F,
F = Pressure x Area to tile
F = 200 x 0.25
F = 2 x 25
F = 50 N
Hence, It can withstand any force less than 50 N.