Correct option is (4) 608
Prime factorisation of the given numbers
25 = 5 x 5
40 = 2 x 2 x 2 x 5
60 = 2 x 2 x 3 x 5
L.C.M of 25, 40 and 60 = 2 x 2 x 2 x 3 x 5 x 5 = 600
The required number is 8 more than the L.C.M, i.e., 600 + 8 = 608
Therefore, the least number which when divided by 25, 40 and 60 leaves remainder 8 in each case is 608.
