Question

Acetyl bromide when reacts with excess of CH₃MgI followed by treatment with saturated solution of NH₄Cl it gives: 

(1)  Acetone 

(2)  Acetamide 

(3)  2-methyl-2-propanol 

(4)  acetyl iodide 

Answer 1

Acetyl bromide when reacts with excess of CH₃MgI followed by treatment with saturated solution of NH₄Cl it gives  2-methyl-2-propanol