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find the area of a quadrilateral with one of its diagonal measuring 6 cm and perpendicular on it form the opposite vertics measuring 7.8 cm and 8.6 CM solve math

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find the area of a quadrilateral with one of its diagonal measuring 6 cm and perpendicular on it form the opposite vertics measuring 7.8 cm and 8.6 CM solve math
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l = 6 cm

h1 = 7.8 cm

h2 = 8.6 cm

Area of quadrilateral = \(\frac 12 (h_1 + h_2) \times d\)

\(= \frac 12 \times (7.8+8.6) \times 6\)

\(= \frac 12 \times 16.4\times 14\)

\(= 16.4 \times 3\)

\(= 49.2\) cm3

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