Differentiate

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PeterPJF · Answer 1 · 2024-11-09T12:08:54+0000

Using the rules for differentiation, we get:

dy/dx = - (x-3)x² / (x+1)⁵

khadarabad · Answer 2 · 2024-12-23T17:13:37+0000

y = (x³)/(1+x)⁴

taking log both sides

log y = 3 logx - 4 log(1+x)

differentiating w.r.to x

(1/y) dy/dx = 3/x - 4/(1+x)

(1/y) dy/dx = (3-x)/[x(1+x)]

dy/dx = [(3-x)y]/[x(1+x)]

dy/dx =[(3-x)x³]/[x(1+x)(1+x)⁴]

dy/dx =[(3-x)x²]/[(1+x)⁵]