Consider a line \( \alpha \bar{z}+\bar{\alpha} z+i \beta=0 \) such that \( -\frac{\alpha}{\bar{\alpha}}=\lambda(1+i), \lambda \in R^{+} \), then the angle made by line with real axis is \( \frac{\pi}{k} \), then \( k \) is \( \qquad \) .
guys give me a shorter way of solving this, i solved converting into cartesian form(which is pretty long ngl) and got the answer 8 which is correct.
