(i) (3,4} c A
This statement is not correct because {3, 4} is element of set^4. Thus, {{3,4}} czA.
Hence, 1 ∈ A, 2 ∈ A, {3,4} ∈ A, 5 ∈ A all these are elements of A.
(ii) (3,4} ∈ A is true because set {3, 4} is element of A.
(iii) {{3, A}}⊂ A is true because {3, 4} is element of set A when we write {{3, 4}} then it becomes set.
Thus, {{3,4}} ⊂ A.
(iv) 1 ∈ A is true because lis element of set A.
(v) 1 ⊂ A is not true because any element cannot be subset of any set until it is written in {} bracket.
(vi) {1, 2, 5} ⊂A is true because {1, 2, 5} is set of elements 1,2,5 of A.
(vii) {1, 2, 5} ∈ A is not true because 1, 2, 5 are elements of set A. Thus, {1,2,5} will be subset of set A.
(viii) {1, 2, 3} ⊂ A is not true because 3 is not an element of set A.
(ix) Φ ∈ A is not true because f .is not elements of set A.
(x) Φ ⊂ A is true because null set Φ is subset of all sets.
(xi) {Φ} ⊂ A is not true because Φ is null set and Φ is element of set {Φ}.