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The number which exceeds 20% of itself by 40, is

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Let the required number be x

Then, \(x - \frac{20\ x}{100} = 40\)

\(\frac{100\ x - 20\ x}{100} = 40\)

\(80 \ x = 40 \times 100\)

\(x = \frac{40 \times 100}{80}\)

\(\therefore \ x = 50\)

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