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in Straight Lines by (15 points)
Find the equation of median of a triangle ABC whose vertices are A (2, 5), B (-4, 9) and C (-2,-1) through A.

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Mid point of B(-4,9) and C(-2,-1)  is D( (-4-2)/2, (9-1) /2 )

D(-3, 4)

Equation of the line passing through A (2,5 )  and  D(-3, 4)

( y-5)/(x - 2) = (4-5)/(-3-2)

( y-5)/(x - 2) = 1/5

5y - 25 = x - 2

x - 5y + 23 = 0

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