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The angle between equipotential surface and electric lines of force is

(A) Zero

 \((B) \ 180^\circ\)

\((C)\ 90^\circ\)

\((D)\ 45^\circ\)

2 Answers

+1 vote
by (57.1k points)
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Best answer

Correct option is (C) \(90^\circ\)

Electric field is always perpendicular to the equipotential surface at any point.

+1 vote
by (74.8k points)

Correct option is : \((C)\ 90^\circ\)

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