Question

Particle A of mass m₁ moving with velocity (√3i + j) ms^-1 collides with another particle B of mass m₂ which is at rest initially. Let V₁ and V₂ be the velocities of particles A and B after collision respectively. If m₁ = 2m₂ and after collision V₁ - (i  + √3) ms^-1, the angle between V₁ and V₂ is:

Answer 1

Before collision:

velocity of particle A, \(u_1 = (\sqrt3 \hat i + \hat j) m/s\)

Velocity of particle B, u₂ = 0

After collision:

Velocity of particle A, \(v_1 = (\hat i + \sqrt3 \hat j) m/s\)

Using conservation of linear momentum

For angle between \(\vec v_1\) and \(\vec v_2\)

So, the angle between \(\vec v_1\) and \(\vec v_2\) is 105°.