Question

The primary and secondary coils of a transformer have 50 and 1500 turns respectively. If the magnetic flux \(\phi\) linked with the primary coil is given by \(\phi\) = \(\phi_0\) + 4t, where \(\phi\) is in webers, t is time in seconds and \(\phi_0\) is a constant, the output voltage across the secondary coil is:

Answer 1

Answer:  (c) 120 volts 

No. of tums across primary N_p = 50

Number of turns across secondary N_s = 1500

Magnetic flux linked with primary,  ϕ  =  ϕ₀ + 4t