Correct option is (2) \(2^{16}\)
\(\operatorname{det} \underbrace{(\operatorname{adj}(\operatorname{adj}(\operatorname{adj}(\operatorname{adj} A))))}_{r \text { times }}=|A|^{(n-1)^r}\)
\(\text { As }|A|=2 \)
\(\therefore \operatorname{det}(\operatorname{adj}(\operatorname{adj}(\operatorname{adj}(\operatorname{adjA})))) =|A|^{(3-1)^4} \)
\(=|A|^{2^4}=|A|^{16} \)
\(=2^{16}\)