Question

In Carius method of estimation of halogen, 0.25 g of an organic compound gave 0.16 g of AgBr. What is the percentage of bromine in the organic compound (Given molar mass of Ag = 108, Br = 80)

Answer 1

Answer is : 27

Moles of AgBr \( = \frac{0.16}{188}moles\) 

Mass of Br  = \(\frac{0.16}{188}\times 80\ g\)

= 0.068 g

\( \% \ of \ Br = \frac{0.068}{0.25}\times 100\)

= 27%