Question

Find heat required to convert of 1 gm ice at –10°C to steam at 110°C.

Answer 1

Answer is : 730

\(\mathrm{Q}=1 \times 0.5 \times 10+1 \times 80+1 \times 1 \times 100+1 \times 540+1 \times 0.5 \times 10\)

\( \mathrm{Q}=5+80+100+540+5=640+90=730\ \mathrm{cal}\)