Applying derivative on both sides we get
xf(x)=x2fI(x)+2xf(x)
-xf(x)=x2fI(x)
\(f^I(x)/f(x)=-1/x\)
Applying integral on both sides we get
f(x)=c/x where c is an constant
given f(x) = 3 when x is 2
so 3=c/2 so c is 6
therefore function is f(x)=x/6
so f(6) is 1