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in Differential equations by (20 points)
Let y = y(x) be the solution of the differential equation

(xy-5x2 √1+x2) dx+(1+x2)dy=0, y(0) = 0. Then y(√3) is equal to

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1 Answer

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\(\frac{dy}{dx} = \frac{5x^2\sqrt{1 + x^2} - xy}{1 + x^2} \)

\(\frac{dy}{dx} + \frac{x}{1 + x^2} y = \frac{5x^2\sqrt{1 + x^2}}{1 + x^2}\)

\(\frac{dy}{dx} + \frac{x}{1 + x^2} y = 5x^2 \frac{1}{\sqrt{1 + x^2}}\)

first-order linear differential equation

\(\frac{dy}{dx} + P(x)y = Q(x)\)

IF = \(e^{\int P(x) dx} = e^{\int \frac{x}{1 + x^2} dx}\)

\(u = 1 + x^2 \)

\(du = 2x dx\)

IF = \(e^{\frac{1}{2} \ln |1 + x^2|} = (1 + x^2)^{1/2}\)

\(y \cdot \text{IF} = \int (\text{IF} \cdot Q) \, dx + C\)

\(y(1 + x^2)^{1/2} = \int 5x^2 dx = \frac{5}{3} x^3 + C\)

y(0) = 0 , C=0

\(y = \frac{5x^3}{3\sqrt{1 + x^2}}\)

\(y(\sqrt{3}) = \frac{5\sqrt{3}}{2}\)

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