Graph between de Broglie wavelength (λD) and kinetic energy (K) of an electron is

Question

Graph between de Broglie wavelength \((\lambda D)\) and kinetic energy (K) of an electron is

Answer 1

Correct option is (2) 

 

de Broglie wavelength \((\lambda_D)\) of an electron of mass (m), moving with velocity (v) is given by 

\(\lambda_D = \frac{h}{mv}\) 

Where h is planck’s constant. 

Kinetic energy (K) = \(\frac{1}{2} mv^2\)  

mv = \(\sqrt{2mk}\)  

\(\lambda_D = \frac{h}{\sqrt{2mK}}\) 

\(\frac{1}{K} = \frac{2m\lambda^2_D}{h^2}\) 

Plot of \(\frac{1}{K}\) vs \(\lambda_D\) is